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Sd06 Pricing in Construction State University of Land Management (GOOSE)

Test task number 15

Rate% physical deterioration of the building, if the chronological age - 20 years, effective - 15 years, and the term of the economic life - 50 years

Test task number 28

The area of \u200b\u200bthe office building of 1 000 sq.m. It was built in 1970. Valuation date - 2000 year. Term economic life - 80 years. Full replacement cost - $ 970 / sq.m., Including the cost of repair - $ 170. / Sq. Rate this building if it does not need emergency repairs

Test task number 35

The total cost of the reproduction of the building - 28 million rubles. Physical deterioration - 25%. The building needs to install air-conditioning system and replacement of plumbing. The cost of installing air-conditioning system in the building of 1250 rubles., And analogous-tech costs for new construction - 870 thousand rubles. Expenditures for the replacement of sanitary equipment - 1350 rubles. Loss of rent due to improper planning of 860 thousand rubles. in year. The gross rental multiplier is 4. Calculate the amount of accumulated depreciation

Test task number 53

Data for the subsequent five tasks (53 - 57)

The object of assessment using the cost method - a detached single-storey building area of \u200b\u200b280 square meters, built 25 years ago. The walls are brick buildings. Covering concrete. Frames and doors are wooden and have not been changed since it was built. The roof is covered with slate, since the construction has not been repaired and a leak. The roofs of houses in the area substantially coated with iron. Plumbing fixtures and lighting devices are in good condition, but outdated and does not meet modern requirements. The interior layout does not meet modern requirements. Recently, the city government organized a one-way traffic on the adjacent street, which made it difficult access to the building.

The estimated construction cost of the building is given to current prices and amounts to 420 000 CU

Specialists in construction gave the following information:

Wear brickwork is assessed as:

Depreciation in. = 0.006 * T * W,

where: T - the age of the building (s);

W - the estimated cost.

Wear ceilings estimated as:

Deterioration n. = (0.002 * T + (S * N) / 5600) * W,

where: T - the age of the building (s);

S - area of \u200b\u200bthe building (square meter);

N - number of floors;

W - the estimated cost.

Depreciation frames and doors is estimated as:

Wear p. = 0.03 * T * Wp

where: T - the age of the building (s);

Wp - the cost of installation frames and doors.

- Installation of doors and frames in the same house costs 16,000 CU

- The roof can not be repaired, its alteration (iron) is estimated at 24 000 CU

- Replacement of plumbing and lighting is estimated at 18 000 CU

- Due to poor planning rent for 1 square meter in the building on the CU 3 month behind adjacent.

- The value of the gross monthly rental multiplitkatora in the region is 60.

- Analysis of the loss in value as a consequence of changes in the traffic on the street adjacent to the neighboring houses gives an average value of 15 000 CU

Determine the magnitude of avoidable physical deterioration

Test task number 54

Initial data are given in the problem number 53

Determine the value of irremovable physical depreciation

Test task number 55

Initial data are given in the problem number 53

Determine the value of disposable functional obsolescence.

Initial data are given in the problem number 53

Determine the value of irremovable functional obsolescence

Test task number 57

Initial data are given in the problem number 53

Determine the magnitude of impairment
GOOSE Sd.06 Pricing in Construction

State University of Land Management (GOOSE)
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